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Posted by markr on 28/6/2009, 5:46 pm, in reply to "Li'l proof thing"
b + 1/(b-1) - a - 1/(a+1) = 2
b - a + [1/(b-1) - 1/(a+1)] = 2
b - a + [(a - b + 2) / (ab - a + b - 1)] = 2
(a - b + 2) / (ab - a + b - 1) = a - b + 2
Therefore,
ab - a + b - 1 = 1
and
ab - a + b = 2
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