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Posted by Moby Dick
on 7/8/2009, 8:15 pm, in reply to "A Major Challenge for True Puzzlers"
I am having trouble coming up with a solution. I wonder if it might be impossible?
Simple arithmetic would suggest that it should be possible: each team plays four others - that's the first four sorted. Each opponent plays 3 other teams. 4*3=12, so that's a potential 4+12=16 opponents either played directly or played via an intermediary. No obvious reason why it might be impossible? Perhaps there's a solution in graph theory?
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