
Posted by NickMcG on 8/8/2009, 5:18 am, in reply to "Even Fairer Method?"
I was only considering the outcome of each game to be win,lose or tie.
If we use A beats C 20-0 and B beats C 19-0 therefore A is better than B then you are absolutely right, Mark.
However, if we stick with win,lose,tie then I think "sum of opponents' scores" is the fairest tiebreak.


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