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Posted by Denis Borris on 18/9/2009, 1:19 pm, in reply to "Re: Li'l algebra..."
Agree.
I was kinda putting that up in disguise, to see
if x=0 is really a solution, since the term
449*x / (x^(-1)*y^(-3)) prevents x=0 (division by zero),
but then term can be written as 449x^2 / y^(-3).
I was trying to remember how these are looked at;
like why (if n=0) is n^1 legal but 1 / n^(-1) is not.
(I have a good memory, but it's short!)
The equation I gave can be simplified to:
x^4 * y^6 = 675 * x^2 * y^3.
Dividing right away by x^2 * y^3 leaves:
x^2 * y*3 = 675.
No need to deal with x=0 (so it appears).
Any ideas?
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