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Posted by NickMcG on 1/11/2009, 10:27 pm, in reply to "Vertex Fun"
Fun?
May have erred but for part 1 I get 9/8*sqrt(4261)
For a parabola y=ax^2+bx+c the vertex as I recall is at (-b/2a, (4ac-b^2)/4a) so part 2 is a bunch of messy algebra which doesn't seem to simplify much:
I get Distance = sqrt(((Ab-Ba)/2aA)^2 + (4aA(c-C)+aB^2-Ab^2)/4aA)^2)
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