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Re: Frozen in time
Posted by Sean A. Irvine on 19/9/2016, 9:58 pm, in reply to "Frozen in time"
I think the published solution to this is wrong. If you make, 13 outward steps you can get sum((19/20.0)^k,k=0..13) = 10.246..., but even with an infinite number of return steps you will never make it back sum((19/20.0)^k,k=14..infinity) = 9.753...
In my solution I used 12 outward steps, which also allows return after 57 hikes.
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